4x^2-16x-356=0

Solution for 4x^2-16x-356=0 equation:

4x^2-16x-356=0

a = 4; b = -16; c = -356;
Δ = b2-4ac
Δ = -162-4·4·(-356)
Δ = 5952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5952}=\sqrt{64*93}=\sqrt{64}*\sqrt{93}=8\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{93}}{2*4}=\frac{16-8\sqrt{93}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{93}}{2*4}=\frac{16+8\sqrt{93}}{8}
$